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  • 15-03-2024
  • Physics
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A proton moves in a circular path perpendicular to a 2.09 T magnetic field. The radius of its path is 7.26 mm. Calculate the energy of the proton?
a) 1.6910⁻¹⁵J
b) 3.3810⁻¹⁵ J
c) 6.7610⁻¹⁵J
d) 1.3510⁻¹⁴ J

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