daisies3305 daisies3305
  • 11-09-2018
  • Mathematics
contestada

Solve for y, y(a-b)=c(y+a)

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gmany
gmany gmany
  • 12-09-2018

[tex]y(a-b)=c(y+a)\ \ \ \ |\text{use distributive property}\\\\ya-yb=cy+ca\ \ \ \ |-cy\\\\ya-yb-yc=ca\\\\y(a-b-c)=ca\ \ \ \ |:(a-b-c)\neq0\\\\\boxed{y=\dfrac{ca}{a-b-c}}[/tex]

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