The point-slope form:
[tex]y-y_1=m(x-x_1)[/tex]
[tex]m[/tex] - slope
[tex](x_1,\ y_1)[/tex] - point
We have the point [tex](3,\ -2)\to x_1=3,\ y_1=-2[/tex] and the slope [tex]m=\dfrac{2}{3}[/tex]
Substitute:
[tex]y-(-2)=\dfrac{2}{3}(x-3)\\\\\boxed{y+2=\dfrac{2}{3}(x-3)}[/tex]
