Let the greater integer be x
Then other integer= x-7
A/q- x(x-7)= 78
=> x^2 -7x-78=0
=> x^2 -13x +6x -78=0
=> x (x-13) +6 (x-13)=0
=> (x-13)(x+6)= 0
So, x=13 or x= -6
since -6 is not a positive integer so the value of
x=13
other integer= x-7=13-7=6
Hence, the numbers are 13 and 6
HOPE IT IS USEFUL
