length of the cylinder = 8 x 20 mm
= 160 mm
radius of the cylinder = 20 mm
so,
volume of the container = πr^2h
[tex] = \frac{22}{7} \times {20}^{2} \times 160[/tex]
= 201142.8571 mm^3
volume of four ornaments ,
[tex] = 4 \times \frac{4}{3} \times \frac{22}{7} \times {20}^{3} [/tex]
=134095.2381 mm^3
