(3x + 4)³ = 2197
Taking the cube root in this case is easier, although we can do it the extended way which is complicated.
[tex] \sqrt[3]{(3x+4)^3} [/tex] = [tex] \sqrt[3]{2197} [/tex]
3x + 4 = 13
Now solve normally.
subtract 4
3x + 4 = 13
-4 -4
3x = 9
Divide by 3 to isolate 3
[tex] \frac{3x}{3} = \frac{9}{3} [/tex]
3 and 3 cancels out
x = 3
