Answer:
Acceleration, [tex]a=8.57\ m/s^2[/tex]
Explanation:
Given that,
Initial speed of the Cheetah, u = 5 m/s
Distance covered, s = 35 m
Final speed of the cheetah, v = 25 m/s
We need to find the acceleration required for the cheetah to reach its final speed. The formula is as follows :
[tex]a=\dfrac{v^2-u^2}{2s}[/tex]
[tex]a=\dfrac{(25)^2-(5)^2}{2\times 35}[/tex]
[tex]a=8.57\ m/s^2[/tex]
So, the acceleration of the cheetah is [tex]8.57\ m/s^2[/tex]. Hence, this is the required solution.
