Answer:
Use basic trigonometric identity
[tex]\tan x =\dfrac{\sin x}{\cos x}[/tex]
Step-by-step explanation:
Use basic trigonometric identity
[tex]\tan x =\dfrac{\sin x}{\cos x}[/tex]
Substitute it into the expression
[tex]\sin x\cos x\tan x=\sin ^2 x:[/tex]
[tex]\\ \\\sin x\cdot \cos x\cdot \dfrac{\sin x}{\cos x}\\ \\=\dfrac{\sin x\cdot \cos x\cdot \sin x}{\cos x}\\ \\=\dfrac{\sin x\cdot \sin x}{1}\ \ [\text{Cancelled}\ \cos x]\\ \\=\sin^2x[/tex]
