Solve for y in terms of x:
[tex]4 {x}^{2} + 8 {x}^{2}y = 8 {x}^{3} [/tex]
A.
[tex] \frac{2}{2x - 1} [/tex]
B.
[tex] \frac{2}{2x + 1} [/tex]
C.
[tex] \frac{2x - 1}{2} [/tex]
D.
[tex] \frac{2}{2x - 1} [/tex]




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