Answer:
Let [tex]g(x)=e^{2x-1}[/tex]
View Graph
Step-by-step explanation:
Let [tex]g(x)=e^{2x-1}[/tex]
find the cutting points with respect to the axes.
We can say that g(x) = y, well then [tex]y=e^{2x-1}[/tex], if x=0 then [tex]y=e^{2x-1}=e^{(2*0-1)}=e^{-1}=0.36787[/tex]
with respect to x there are no cut points since it is an asymptote
To x=1 y≅2.718, x=-1 y≅0.049, x=2 y≅20.08, x=-2 y≅0.0067, this for plotting some values
