Answer:
[tex]\frac{2x}{x+7}[/tex]
Step-by-step explanation:
we have
[tex](\frac{x-3}{x+7})(\frac{2x}{x-3})[/tex]
When multiply two fractions:
Multiply the numerators of the fractions to get the new numerator.
Multiply the denominators of the fractions to get the new denominator
so
[tex](\frac{x-3}{x+7})(\frac{2x}{x-3})=\frac{(x-3)(2x)}{(x+7)(x-3)}[/tex]
(x-3) cancels out
[tex]\frac{2x}{x+7}[/tex]
