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  • 12-02-2020
  • Mathematics
contestada

Write an equation of a line that is through (6,-3) and is perpendicular to 3x+y=6

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TakeLCuzIHaveW
TakeLCuzIHaveW TakeLCuzIHaveW
  • 13-02-2020

Answer: y=-1/3x-1

Step-by-step explanation:

1) Isolate y by subtracting 3x from both sides.

3x+y=6 -> y=3x+6

2) Find the negative inverse of 3- which is -1/3.

3) Use y=mx+b and plug in what you know.

-3=-1/3(6)+b

4) Solve for b.

-3=-2+b

-1=b

5) Put it all together in y=mx+b format.

y=-1/3x-1

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