recklessangel recklessangel
  • 13-02-2020
  • Mathematics
contestada

Determine the equation of the line that is perpendicular to the line y = 3x + 4 and passes through the point (6, 2).

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laurellee27
laurellee27 laurellee27
  • 13-02-2020

Answer:

y = -1/3x + 4

Step-by-step explanation:

Perpendicular lines: Their gradients are reciprocals.

This means:

  • -1 ÷ Gradient 1 = Gradient 2
  • Gradient 1 * Gradient 2 = -1

Gradient of the given equation is 3.

-1 / 3 = -1/3

Gradient of the equation we're finding is -1/3

y = -1/3x + c

Substitute the coordinates in to find the value of c

2 = -1/3(6) + c

2 = -2 + c

2 + 2 = c

4 = c

y = -1/3x + 4

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