Respuesta :

Danboghiu66

At the denominator you have

(x-5)×4=4x-20.

But:

2(x+4)/(4(x-5))=(x+4)/2/(x-5)

Answer:

see explanation

Step-by-step explanation:

Given

[tex]\frac{2(x+3)(x+4)}{(x+1)(x-5)}[/tex] × [tex]\frac{(x+1)}{4(x+3)}[/tex]

Cancel the common factors (x + 1), (x+3) on the numerator/ denominator

and cancel 2 and 4 on the numerator/ denominator by 2

= [tex]\frac{x+4}{2(x-5)}[/tex]

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