Which is the solution for log(3x - 1) + log 2 = log 4 + log (x + 2) ?

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13-05-2020
Mathematics

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Which is the solution for log(3x - 1) + log 2 = log 4 + log (x + 2) ?

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Chelboy Chelboy · Answer 1 · 2020-05-17T23:43:54+02:00

Chelboy Chelboy

17-05-2020

Answer:x=1

Step-by-step explanation:

log(3x-1)+log2=log4+log(x+2)

log(2(3x-1))=log(4(x+2))

Cancel log on both sides

2(3x-1)=4(x+2)

Open brackets

6x-2=4x+8

Collect like terms

6x-4x=8+2

10x=10

Divide both sides by 10

10x/10=10/10

x=1

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AnyeLovesLearning AnyeLovesLearning · Answer 2 · 2020-05-21T01:02:20+02:00

AnyeLovesLearning AnyeLovesLearning

21-05-2020

Answer:

x=5

Step-by-step explanation:

log(3x-1)+log2=log4+log(x+2)

log(2(3x-1))=log(4(x+2))

Cancel log on both sides

2(3x-1)=4(x+2)

Open brackets

6x-2=4x+8

Collect like terms

6x-4x=8+2

2x=10

Divide both sides by 2

2x/2=10/2

x=5

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Which is the solution for log(3x - 1) + log 2 = log 4 + log (x + 2) ?​

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Which is the solution for log(3x - 1) + log 2 = log 4 + log (x + 2) ?