afnfbree afnfbree
  • 15-05-2020
  • Mathematics
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Frank measured 56 cm. The actual length was 61 cm. Which expression shows his percent error?

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allison1123
allison1123 allison1123
  • 15-05-2020

Answer: 8.54701% difference

Step-by-step explanation: (61-56)/[(61+56)/2] x 100= 8.55%

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