Answer:
9in²
Step-by-step explanation:
Area of a triangle = 1/2 × base × height
For ∆BAC, base = 2in and area = 6in²
Substituting to get the height of the triangle
6 = 1/2 × 2 × h
6 = h
Height = 6in
Since ∆BAC ~ ∆EDF, then they will approximately have the same height. Given base of ∆EDF = 3in
Area of ∆EDF = 1/2bh
Area of ∆EDF = 1/2 × 3 × 6
Area of ∆EDF = 9in²
