victorchuku
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A driver moves with initial velocity of 40m/s accelerates uniformly at a rate of 12m/s2.  It attains a velocity 52m/s. calculate the distance covered during the journey.

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Respuesta :

Answer:

distance=46m

Explanation:

initial velocity(u)=40m/s

final velocity(v)=52m/s

acceleration=12m/s²

distance(s)=?

v²=u²+2as (using equ.of motion)

(52)²=(40)²+2(12)s

2704=1600+24s

24s=2704-1600

24s=1104

s=1104/24

s=46m

The distance covered during the journey is 46m.

To find the answer, we need to know about the Newton's equation of motion.

What are the Newton's equation of motion?

Newton's equation of motion are

  • V=U+at
  • S=Ut+1/2at²
  • V²-U²=2×a×S

Where S=distance

            U=initial velocity

            V=final velocity

            t=time

            a= acceleration

What is the distance covered by the driver, if the driver has initial velocity 40m/s, final velocity 52 m/s and acceleration 12 m/s²?

  • Here, U=40m/s, V=52m/s and a= 12 m/s²
  • So, 52²-40²=2×12×S

     =>2704-1600=24×S

     =>1104=24S

     =>S=1104/24=46m

Thus, we can conclude that the distance covered during the journey is 46m.

Learn more about the Newton's equation of motion here:

brainly.com/question/8898885

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