auroratorres695 auroratorres695
  • 12-07-2020
  • Mathematics
contestada

Consider the following quadratic equation. -4x^2+bx-11=0 Determine a possible value of b so that the quadratic has two complex solutions.

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Alfpfeu
Alfpfeu Alfpfeu
  • 12-07-2020

Answer:

Step-by-step explanation:

hello,

for [tex]ax^2+bx+c=0[/tex]

[tex]\Delta = b^2-4ac[/tex]

so here

[tex]\Delta = b^2-4*(-4)*(-11)=b^2-176[/tex]

to have two complex solutions we need [tex]\Delta < 0\\[/tex]

so [tex]b^2<176[/tex]

[tex]<=> b < \sqrt{176}=13.266...[/tex]

for instance we can take b = 0

hope this helps

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lolaj0209 lolaj0209
  • 27-10-2021

Answer:

The correct answer is 12.

Step-by-step explanation:

i got it correct on my test, thanks to comment on the question above.

Answer Link

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