HyperPro195
HyperPro195 HyperPro195
  • 14-07-2020
  • Mathematics
contestada

help with this I don't know how to solve

help with this I dont know how to solve class=

Respuesta :

Preussischer
Preussischer Preussischer
  • 14-07-2020

Answer:

The right answer is the first option, [tex]tg= \frac{\sqrt{105}}{4}[/tex]

Step-by-step explanation:

The tg is the ratio of the opposite cathet to the adjacent cathet .

Here b is the opposite cathet, с is the hypotenuse and b is an adjacent cathet.

[tex]tg = \frac{b}{a}[/tex]

Let's find b.

[tex]c^2=a^2+b^2\\ b^2=c^2-a^2\\ b^2=22^2-8^2\\ b^2=484-64\\ b^2=420\\ b=\sqrt{420} = \sqrt{2*21*2*5} = 2\sqrt{105}[/tex]

Now let's find tgθ.

[tex]tg = \frac{b}{a} \\ tg = \frac{2\sqrt{105}}{8} \\ tg=\frac{\sqrt{105}}{4}[/tex]

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