Answer:
the stone fell in the air for 7 sec and fell in the water for 5 sec
Let time taken in air be 'a'
And the time taken in water be 'b'
a+b=12
Distance covered in air = 16a
′′′′′ ′′″″ water= 3b
16a + 3b = 127
Solve the two equations simultaneously
a= 7 secs
b= 5 secs
