Answer:
Hey there!
First, we want to find the side length of the large triangle.
1/2bh=y cm^2
bh=2y cm^2
Since b and h are the same here, we have b^2= 2y, [tex]b=\sqrt{2y}[/tex].
And we have FC=[tex]\frac{\sqrt{2y} }{2}[/tex].
Area of shaded triangle: [tex]\frac{1}{2} (\frac{\sqrt{2y} }{2})(\frac{\sqrt{2y} }{2})[/tex].
This is equal to: [tex]\frac{1}{2}(\frac{2y}{4})[/tex], or y/4.
Let me know if this helps :)
