Answer:
115 g
Explanation:
Step 1: Given data
- Molar mass of glucose: 180.2 g/mol
- Volume of solution: 2.00 L
- Molarity of the solution: 0.318 M
Step 2: Calculate the moles of glucose
The molarity is equal to the moles of solute divided by the liters of solution.
M = moles of glucose / liters of solution
moles of glucose = M × liters of solution
moles of glucose = 0.318 mol/L × 2.00 L
moles of glucose = 0.636 mol
Step 3: Calculate the mass corresponding to 0.636 moles of glucose
0.636 mol × 180.2 g/mol = 115 g
