20064871
20064871 20064871
  • 13-11-2020
  • Mathematics
contestada

Write the equation of the line y=(5)/(6)x+(7)/(6) perpendicular to
that passes through the point (-8,7)

Respuesta :

ackahedem582
ackahedem582 ackahedem582
  • 13-11-2020

Answer:

6x + 5y + 13 = 0.

Step-by-step explanation:

y = 5/6x + 7/6

Gradient = 5/6

Since the line is perpendicular to y = 5/6x + 7/6

then its gradient is -6/5.

Hence its equation is: point (-8,7).

y - 7 = -6/5(x -(-8))

multiplying through by 5 we get;

5y - 35 = -6(x + 8)

5y - 35 = -6x - 48

6x + 5y + 13 = 0

Answer Link

Otras preguntas

A polynomial function upper P left parenthesis x right parenthesis with rational coefficients has the given roots. Find two additional roots of upper P left par
How do you factor out a GCF?
¿Cómo se dice “You (all) are sports-minded” en español?
Why has farming in the Midwest become big business?
What is 4p-11-p=2+2p-20
Please answer the questions.
Please help me with this math question I need help immediately I will give brainliest thanks
what would happen if the body could not get enough oxygen
If a chicken farm sold 3000 dozen egg last week how many individual egg were sold
What is a point-slope equation of the line with slope –13 that goes through the point (5, 7)? A.y – 7 = –13(x – 5) B.y – 5 = –13(x – 7) C.y + 5 = –13(x + 7) D.y