Answer:
Centre (5,-1) radius =2
Step-by-step explanation:
(x-5)^2+(y+1)^2=4
The standard equation of the circle is
(X-a)^2+(y-b)^2=r^2
Where a,b is centre of the circle and r is the radius of the circle
Compare the equations
So we get a=5,b=-1 and r=2
Centre (5,-1) radius =2
