Faithrt Faithrt
  • 11-12-2020
  • Mathematics
contestada

H(t)=-16(t-1)^2+16
What is the maximum height the ball reaches and how long does it take?

Respuesta :

VectorFundament120
VectorFundament120 VectorFundament120
  • 11-12-2020

Given t = time and h = height

[tex]h(t) = - 16(t - 1)^{2} + 16[/tex]

From the equation.

[tex]y = a(x - h)^{2} + k[/tex]

h is the axis od symmetry

(h, k) is the vertex.

In the equation, h is 1 and k is 16.

So the maximum value is 16 at t = 1.

The ball reaches maximum at 16 and it takes t = 1 to reach the maximum point.

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