Answer:
8/3 square units.
Step-by-step explanation:
First, visualize the area. You can refer to the attachment below.
To find the area then, we will integrate y from x = 0 to x = 2. Therefore:
[tex]\displaystyle A=\int_0^2x^2\, dx[/tex]
Integrate:
[tex]\displaystyle A=\frac{1}{3}x^3\Big|_{0}^2[/tex]
Evaluate:
[tex]\displaystyle A=\frac{1}{3}[2^3-0^3]=\frac{1}{3}(8)=\frac{8}{3}[/tex]
The area is 8/3 square units.
