Answer:
0.589 moles
Explanation:
1 mol of any gas at STP (Standard Temperature and Pressure) occupies 22.4 L. So, we can define the ratio: 1 mol/22.4 L.
According to that, we can multiply the volume of NFCI₃ gas by the ratio, to obtain the number of moles there is in that volume:
moles of NFCI₃ = 13.2 L x 1 mol/22.4 L = 0.589 moles
Therefore, in 13.2 L of NFCI₃ gas, there are 0.589 moles.
