Answer:
f(2+h)=-(h+2/3)^2+1/4
f(x+h)=-(x+h-1/2)^2+1/4
Step-by-step explanation:
1. f(2+h)=(2+h)-(2+h)^2=2+h-4-4h-h^2=-h^2-3h-2=-(h^2+3h+2)
=-(h+2/3)^2+1/4
2. Let (x+h)=a, then rewrite the equation into f(a)=a-a^2.
a-a^2=-(a^2-a)=-[(a-1/2)^2-1/4]=-(a-1/2)^2+1/4.
Insert a=x+h, f(x+h)=-(x+h-1/2)^2+1/4
