Answer:
[tex][H^+]=[OH^-]=1.0x10^{-7}M[/tex]
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to calculate the relative concentrations by using the following equations:
[tex]pH+pOH=14\\\\pH=-log([H^+])\\\\pOH=-log([OH^-])[/tex]
Thus, we realize that both pH and pOH are the same, 7, so that the concentration of H⁺ and OH⁻ are virtually the same, and can be calculated as follows:
[tex][H^+]=[OH^-]=10^{-7}=1.0x10^{-7}M[/tex]
Regards!
