iriscantarero67 iriscantarero67
  • 14-06-2021
  • Mathematics
contestada

Find two consecutive positive integers such that the square of the
smaller integer is nineteen more than five times the larger integer.

Respuesta :

clarch19
clarch19 clarch19
  • 14-06-2021

Answer:

8 and 9

Step-by-step explanation:

let 'n' = smaller positive integer

let 'n+1' = larger

n² = 5(n+1)+19

n² = 5n + 5 + 19

n² = 5n + 24

n² - 5n - 24 = 0

(n-8)(n+3) = 0

n = 8  [this is the smaller positive integer]

n+1 = 9  [this is the larger positive integer]

n = -3  [this value can be discounted because it is not positive]

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