18bolliha 18bolliha
  • 14-12-2016
  • Mathematics
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2tan∅+2=0 solve each equation for 0≤∅≤2π

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1davey29
1davey29 1davey29
  • 14-12-2016
First, solve for tanØ. 2tanØ+2=0, subtract 2, 2tanØ=-2, divide 2, tanØ=-1. Now, tanØ is only one at 45 degree angles, which in radians is π/4, 3π/4, 5π/4, and 7π/4. For tanØ to be negative, it must be in the second or fourth quadrant. The only answer choices in those quadrants that fit the domain restriction are 3π/4 and 7π/4, making those your answers.
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