LHS
[tex]\\ \sf\longmapsto \dfrac{cos(90-\Theta)}{sin\Theta}+\dfrac{sin\Theta}{cos(90-\Theta)}[/tex]
[tex]\boxed{\sf cos(90-A)=sinA}[/tex]
[tex]\\ \sf\longmapsto \dfrac{sin\Theta}{sin\Theta}+\dfrac{sin\Theta}{sin\Theta}[/tex]
[tex]\\ \sf\longmapsto 1+1[/tex]
[tex]\\ \sf\longmapsto 2[/tex]
Hence proved
