Answer:
≈147.86 (m.)
Explanation:
1) if the acceleration is a=(V-V₀)/t, where V₀ - initial velocity (25), V - final velocity (2), t - elapsed time, then
t=(V-V₀)/a=23/2.1 (sec.);
2) the required distance can be calculated according to the formula:
S=V₀t+0.5(at²), where V₀=25; t=23/2.1; a= -2.1;
3) [tex]S=\frac{25*23}{2.1} -\frac{2.1*23^2}{2*2.1^2}=\frac{27*23}{4.2}=147.86(m.)[/tex]
