hello56784 hello56784
  • 02-11-2021
  • Mathematics
contestada

Solve Tan^2 theta= 1+sec theta

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27tristenjones
27tristenjones 27tristenjones
  • 02-11-2021

Answer:sec0

Step-by-step explanation:

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lynnkc2000 lynnkc2000
  • 02-11-2021

Answer:

sec θ = -1           θ = π+2nπ

sec θ = 2            θ = π/3+2nπ    or   5π/3+2nπ

Step-by-step explanation:

tan² θ = 1 + sec θ

sec² θ - 1 = 1 + sec θ

sec² θ - sec θ - 2 = 0

(sec θ + 1) (sec θ - 2) = 0

sec θ = -1           θ = π+2nπ

sec θ = 2            θ = π/3+2nπ    or   5π/3+2nπ

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