Respuesta :

  • A right isosceles triangle has legs that are each 10 mm.
  • Here, base (b) = 10 mm
  • Height (h) = 10 mm
  • Let the length of the hypotenuse be x.
  • Therefore, in the right triangle

[tex](b) ^{2} + {(h)}^{2} = {(x)}^{2} \: \: \: ( by \: \: \: pythagoras \: \: \: theorem)\\ = > {(10)}^{2} + {(10)}^{2} = {(x)}^{2} \\ = > 100 + 100 = {x}^{2} \\ = > 200 = {x}^{2} \\ = > x = \sqrt{200} mm \\ = > x = \sqrt{2 \times 2 \times 2 \times 5 \times 5}mm \\ = > x = 2 \times 5 \sqrt{2} mm \\ = > x = 10 \sqrt{2} mm[/tex]

  • So, the length of the hypotenuse is 10√2 mm.

Answer:

10√2 mm.

Hope you could get an idea from here.

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