jennifermg081292 jennifermg081292
  • 16-02-2022
  • Mathematics
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Find the value of X

Find the value of X class=

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Аноним Аноним
  • 16-02-2022

[tex] \sf \leadsto \cos(45) \degree = \dfrac{25}{x} [/tex]

[tex] \\ [/tex]

[tex] \sf \leadsto \dfrac{1}{ \sqrt{2} } = \dfrac{25}{x} [/tex]

[tex] \\ [/tex]

squaring both sides:

[tex] \sf \leadsto \dfrac{1}{ 2 } = \dfrac{625}{x {}^{2} } [/tex]

[tex] \\ \\ [/tex]

[tex] \sf \leadsto {x}^{2} = 625 \times 2[/tex]

[tex] \\ [/tex]

[tex] \sf \leadsto {x}^{2} = 1250[/tex]

[tex] \\ \\ [/tex]

[tex] \sf \leadsto {x} = \sqrt{1250} [/tex]

[tex] \\ \\ [/tex]

[tex] \sf \leadsto {x} = 35.355 \{approx \}[/tex]

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