Answer:
c) 2.7 g
Explanation:
The first step is to find the moles of aluminum that you're reacting. To do this, you would do
24 g × molar mass of aluminum = 24 g ÷ 26.982 g/mol = 0.8895 mol Al
Then by the balanced equation, you know that every 2 moles of Al will produce 3 moles of H2. This implies that 0.8895 × (3/2) = 1.334 moles of H2 will be produced
Lastly to find the mass of H2 produced, multiply the moles of H2 produced by the molar mass of H2
1.334 mol × (2 × 1.008 g/mol) = 2.69 g ≈ 2.7 g
