yhixd
yhixd yhixd
  • 12-04-2022
  • Mathematics
contestada

Evaluate 9x^2y^−2 for x = –3 and y = 2.

a)9(−6)^0
b)1/144
c)20 1/4
d)324

Respuesta :

profarouk profarouk
  • 14-04-2022

Answer:

c)20 1/4

Step-by-step explanation:

[tex]9x^{2}y^{-2}[/tex]

If We replace x by -3 and y by 2 we get  :

[tex]9\left( -3\right)^{2} \left( 2\right)^{-2}[/tex]

Or we have :

[tex]\left( -3\right)^{2} =9\ \text{and} \ \left( 2\right)^{-2} =\frac{1}{2^{2}} =\frac{1}{4}[/tex]

then

[tex]9\left( -3\right)^{2} \left( 2\right)^{-2}=9\times9\times\frac{1}{4} = \frac{81}{4}[/tex]

on the other hand :

[tex]\frac{81}{4} =\frac{80+1}{4} =\frac{80}{4} +\frac{1}{4} =20+\frac{1}{4}=20\frac{1}{4}[/tex]

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