Answer:
[B] [tex]y=log_3x[/tex]
Step-by-step explanation:
Given:
[tex]y=3^x[/tex]
Exchange the variables:
[tex]x=3^y[/tex]
Putting the variable y on the left side of the equation:
[tex]3^y=x[/tex]
Applying the logarithm properties:
[tex]y=log_3(x)[/tex]
Thus,
[tex]f^-^1=log_3(x)[/tex]
Hence, the answer is [B] [tex]y=log_3x[/tex]
~lenvy~
