brownk23 brownk23
  • 02-02-2017
  • Mathematics
contestada

Start at 12. Create a pattern that multiplies each number by 4. Stop when you have 5 numbers

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StewieTwombly
StewieTwombly StewieTwombly
  • 02-02-2017
12, 48, 192, 768, 3072/
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praxer praxer
  • 02-02-2017
Well, I think this is much better viewed in python:
#Start at 12. Create a pattern that multiplies each number by 4. Stop when you have 5 numbers
req_list = [12]i = 1while i < 5:    for b in req_list:        b = b * 4    i += 1    req_list.append(b)print(req_list)    
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