The tensile stress of the wire supporting 2 kg mass is determined as 6.1 x 10⁷ N/m².
Tensile stress of the wire
The tensile stress of the wire is calculated as follows;
σ = F/A
where;
A = πr² = πD²/4
where;
A = π x (0.64 x 10⁻³)²/4
A = 3.22 x 10⁻⁷ m²
σ = F/A = (mg)/A = (2 x 9.8)/( 3.22 x 10⁻⁷)
σ = 6.1 x 10⁷ N/m²
Learn more about tensile stress here: https://brainly.com/question/25748369
#SPJ1
