Answer:
[tex]\frac{(5+a)}{(a-1)}[/tex]
Choice A
Step-by-step explanation:
[tex]f\left(x\right)\:=\:\frac{\left(3+x\right)}{\left(x-3\right)}[/tex]
[tex]x = a + 2[/tex]
Substitute x with a+2
Numerator becomes [tex]3 + (a+2) = 5+a[/tex]
Denominator becomes [tex](a+2) - 3 = a+2-3 = a - 1[/tex]
Therefore the fraction becomes [tex]\frac{(5+a)}{(a-1)}[/tex]
