LailanniI192803 LailanniI192803
  • 03-11-2022
  • Mathematics
contestada

The area of a rectangle is given by a=6x^2y+4y^2x and the width of the rectangle is w=2xy. what is the length, l, of the rectangle if l=a/w

Respuesta :

RafaelI327675 RafaelI327675
  • 03-11-2022

Step 1

Given; The area of a rectangle is given by a=6x^2y+4y^2x and the width of the rectangle is w=2xy. what is the length, l, of the rectangle if l=a/w?

Step 2

[tex]\begin{gathered} l=\frac{a}{w} \\ l=\frac{6x^2y+4y^2x}{2xy} \end{gathered}[/tex][tex]\begin{gathered} factorize \\ l=\frac{2xy\left(3x+2y\right)}{2xy} \end{gathered}[/tex]

Thus;

[tex]l=3x+2y[/tex]

Answer;

[tex]l=3x+2y[/tex]

Answer Link

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