ChaseM449791 ChaseM449791

03-11-2022
Mathematics

contestada

RIn this figure, sin ZQOP = cos 2and cos ZROQ = sin 2

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YetzalyH596264 YetzalyH596264

03-11-2022

So, Sin QOP = QP/OQ = OPPOSITE/ Hyp

Then, cos PQO = QP/OQ = Adjacent/ Hyp

Using the same logic, Cos ROQ = RO/OQ = Adj/Hyp

Then, sin QPO = RO/OQ = Opp/Hyp

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