kaytee24 kaytee24
  • 11-04-2017
  • Mathematics
contestada

Factor 6y2 + 13y + 15.
A) (2y + 1)(3y + 5)
B) (3y + 1)(2y + 5)
C) (2y + 1)(4y + 5)
D) (2y + 5)(3y + 5)

Respuesta :

Аноним Аноним
  • 14-04-2017
[tex]6y^2 + 13y + 15 : \text{Factor}[/tex] 
   
       In general, given [tex]a{x}^{2}+bx+c[/tex] the factored form is: 

[tex]a(x- \dfrac{-b+ \sqrt{b^2-4ac} }{2a})(x-\dfrac{-b- \sqrt{b^2-4ac}}{2a} [/tex] 
 
       In this case, a=6, b=13 and c=15. 

[tex]6(y- \dfrac{-13+ \sqrt{13^2-4*6*15}}{2*6})(y- \dfrac{-13- \sqrt{13^2-4*6*15}}{2*6}) [/tex] 

[tex]6(y- \dfrac{-13+ \sqrt{191i} }{12}(y-\dfrac{-13- \sqrt{191i} }{12}[/tex]

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