Let one of the number be x.
The other two numbers are x+1 and x+2.
The sum of three consecutive numbers is twelve less than six times the lowest number.
⇒ x + (x+1) + (x+2) - 12 = 6x
⇒ x + x +1 + x + 2 - 12 = 6x
⇒ 3x + 9 = 6x
⇒ 3x = 9
⇒ x = 3
Find the numbers:
x = 3
x + 1 = 4
x + 2 = 5
Answer : The numbers are 3, 4 and 5
